# You asked: How many necklaces can be formed with 8 colored beads?

Contents

2520 Ways 8 beads of different colours be strung as a necklace if can be wear from both side.

## How many necklaces are in 8 beads?

Eight different beads can be arranged in a circular form in (8-1)!= 7! Ways. Since there is no distinction between the clockwise and anticlockwise arrangement, the required number of arrangements is 7!/2=2520.

## How many different bangles can be formed from 8 different colored beads?

How many different bangles can be formed from 8 different colored beads? Answer: 5,040 bangles .

## How many ways can 8 differently colored beads be threaded on a string?

Total of permutations = 2,520+3*1,680 = 7,560.

## How many necklaces can be formed with 7 beads?

It would be 7! = 5040 diffrent necklaces.

## How many necklace can be formed with a different Coloured beads?

2520 Ways 8 beads of different colours be strung as a necklace if can be wear from both side.

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## How many necklaces can be made with these beads of different Colours?

The correct answer is 2952 .

## How many necklaces of 12 beads each can be made from 18 beads of various Colours?

Correct Option: C

First, we can select 12 beads out of 18 beads in 18C12 ways. Now, these 12 beads can make a necklace in 11! / 2 ways as clockwise and anti-clockwise arrangements are same. So, required number of ways = [ 18C12 . 11! ] / 2!

## How many bracelets can be made by stringing 9 different colored beads together?

by stringing together 9 different coloured beads one can make 9! (9 factorial ) bracelet. 9! = 9×8×7×6×5×4×3×2×1 = 362880 ways.

## How many different bangles can be formed from ten different colored beads?

This is called a cyclic permutation. The formula for this is simply (n-1)!/2, since all the beads are identical. Hence, the answer is 9!/2 = 362880/2 = 181440.

## How many ways can 6 differently Coloured beads be threaded on a string?

= 720 possible arrangements.